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研究生高等數學

設π/4-x=t,則dx=-dt。

積分極限:x=0,t =π/4;x=π/4,t=0

原公式= ∫ (0,π/4)(π/4-t)dt/[Costco(π/4-t)]

=∫(0,π/4)π/4dt/[Costco(π/4-t)]-∫(0,π/4)TDT/[Costco(π/4-t)]

因為不同的變量不影響最終的積分值,所以:

∫(0,π/4)TDT/[Costco(π/4-t)]=∫(0,π/4) xdx/[cosxcos(π/4-x)]

然後:∫ (0,π/4)xdx/[cosx cos(π/4-x)]= 1/2∫(0,π/4)π/4dt/[Costco(π/4-t)]

和∫(0,π/4)π/4dt/[Costco(π/4-t)]

=∫(0,π/4)π/4dt/[Costcoπ/4 cost+sinπ/4 Sint]

=√2π/4∫(0,π/4) dt/[cost(cost+sint)]

=√2π/4∫(0,π/4) d(tant)/(1+tant)

=√2π/4ln(1+tant)|(0,π/4)

=√2πln2/4

那麽:∫ (0,π/4)xdx/[cos xcos(π/4-x)]=√2πLN2/8。