(25^X)^Y=2000^y
即25 xy = 2000 y ①。
80^y=2000
(80^y)^x=2000^x
即80 xy = 2000 x ②
① * ② Get (25 * 80) xy = 2000 (x+y)
2000^xy=2000^(x+y)
所以xy=x+y
X+Y-XY
=xy-xy
=0